CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    The inverse of 2010 in the group \[{{Q}^{+}}\] of all positive rational under the binary operation * defined by \[a*b=\frac{ab}{2010},\forall \,a,b\in {{Q}^{+}},\] is

    A) \[2009\]                              

    B) \[2011\]

    C) \[1\]                                     

    D) \[2010\]

    Correct Answer: D

    Solution :

     By inspection of binary operation (*) over; \[a*b=\frac{ab}{2010},\forall \,\,a,\,b,\,\in {{Q}^{+}}\]                 2010 is the identity element. And also w e know that, the inverse of identity Hence,  inverse of \[2010=2010\]


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