CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    A space vector makes the angles \[{{150}^{o}}\] and \[{{60}^{o}}\] with the positive direction of x-and y-axes. The angle made by the vector with the positive direction z-axis is

    A) \[{{90}^{o}}\]                                    

    B) \[{{60}^{o}}\]

    C) \[{{180}^{o}}\]                                 

    D) \[{{120}^{o}}\]

    Correct Answer: A

    Solution :

     We know that, the condition when a space vector makes the angles \[\alpha ,\beta \] and \[\gamma \] with the positive direction of \[x,y\] and z-axes respectively is \[{{\cos }^{2}}\alpha +{{\cos }^{2}}\beta +{{\cos }^{2}}\gamma =1\]        ……(i) Given that, \[\alpha ={{150}^{o}},\beta ={{60}^{o}},\gamma =?\] From Eq. (i), \[{{\cos }^{2}}{{150}^{o}}+\beta ={{60}^{o}},co{{s}^{2}}\gamma =1\] \[(si{{n}^{2}}{{60}^{o}}+{{\cos }^{2}}{{60}^{o}})+{{\cos }^{2}}\gamma =1\]                                 \[1+{{\cos }^{2}}\gamma =1\] \[\Rightarrow \]               \[{{\cos }^{2}}\gamma =0\] \[\Rightarrow \]               \[\cos \gamma =0=\cos {{90}^{o}}\] \[\Rightarrow \]               \[\gamma ={{90}^{o}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner