A) 0.0355 g
B) 0.071 g
C) \[6.023\times {{20}^{21}}\]molecules
D) 0.02 mol
Correct Answer: A
Solution :
Ideal gas equation is \[pV=nRT\] When V and T are same, \[p\propto n\] Thus, when number of moles, ie, n is least, it will exert least pressure. (a) \[n=\frac{wt}{mol.\,wt}=\frac{0.0355}{35.5}=1\times {{10}^{-3}}mol\] (b)\[n=\frac{number\text{ }of\text{ }molecules}{{{N}_{A}}}\] \[=\frac{6.023\times {{10}^{21}}}{6.023\times {{10}^{23}}}=0.01\,\,mol\] \[(d)\,\,n=0.02\,\,mol\] Thus, 0.0355 g chlorine will exert the least pressure.
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