CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    For one mole of an ideal gas, increasing the temperature from \[{{10}^{o}}C\] to \[{{20}^{o}}C\]

    A) increases the average kinetic energy by two times

    B) increases the rms velocity by \[\sqrt{2}\] times

    C) increases the rms velocity by two times

    D) increases both the average kinetic energy and rms velocity, but not significantly

    Correct Answer: D

    Solution :

    Given,   \[{{T}_{1}}=273+10=283\,K\]                 \[{{T}_{2}}=273+20=293\,K\] Average \[KE=\frac{3}{2}KT\]                 \[\frac{(K{{E}_{1}})}{(K{{E}_{2}})}=\frac{283}{293}=0.96\] Root mean square (rms) velocity,                 \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\]m                 \[\frac{{{v}_{{{(rms)}_{1}}}}}{{{v}_{{{(rms)}_{2}}}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\]                 \[=\sqrt{\frac{283}{293}}=0.98\] Thus, both average kinetic energy and root mean square velocity increase but not significantly when temperature is increased from \[{{10}^{o}}C\] to \[{{20}^{o}}C\].


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