A) \[\Delta H>0\] and \[\Delta S<0\]
B) \[\Delta H<0\] and \[\Delta S<0\]
C) \[\Delta H>0\] and \[\Delta S>0\]
D) \[\Delta H<0\] and \[\Delta S>0\]
Correct Answer: B
Solution :
Adsorption is an exothermic process, thus AH is negative (ie,\[\Delta H<0\]). Moreover, adsorption results in more ordered arrangements of molecules, thus entropy decreases (ie, \[\Delta S<0\]). \[\Delta G=\Delta H-T\Delta S\] Hence, low temperature favours the reaction.
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