CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    The forbidden energy gap in Ge is 0.72 eV, Given, \[hc=12400\text{ }eV-\overset{o}{\mathop{A}}\,\]. The maximum wavelength of radiation that will generate electron hole pair is

    A) \[172220\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    B)   \[172.2\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]  

    C) \[17222\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) \[1722\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

    Energy gap. \[{{E}_{g}}=\frac{hc}{\lambda }\] \[\lambda =\frac{hc}{{{E}_{g}}}=\frac{12400}{0.72}=17222\overset{o}{\mathop{A}}\,\]


You need to login to perform this action.
You will be redirected in 3 sec spinner