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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    Water is in streamline flows along a horizontal pipe with non-uniform cross-section. At a point in the pipe where the area of cross section is \[10\text{ }c{{m}^{2}}\], the velocity of water is \[1\text{ }m{{s}^{-1}}\] and the pressure is 2000 Pa. The pressure at another point where the cross sectional area is \[5\text{ }c{{m}^{2}}\] is

    A) 4000 Pa                

    B) 2000 Pa

    C) 1000 Pa                

    D) 500 Pa

    Correct Answer: D

    Solution :

    According to equation of continuity                 \[{{A}_{1}}{{v}_{1}}={{A}_{2}}{{v}_{2}}\]                 \[10\times 1=5\times {{v}_{2}}\]                 \[{{v}_{2}}=2\,m/s\]                 \[\frac{{{p}_{1}}}{\rho }+\frac{v_{1}^{2}}{2}=\frac{{{p}_{2}}}{\rho }+\frac{v_{2}^{2}}{2}\]                 \[=\frac{2000}{1000}+\frac{{{1}^{2}}}{2}=\frac{{{p}_{2}}}{1000}+\frac{{{2}^{2}}}{2}\] \[\Rightarrow \]                               \[{{p}_{2}}=500\,Pa\]


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