CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    The length of the chord joining the points\[(4\,\cos \theta ,4sin\theta )\] and  \[(4\,\cos (\theta +{{60}^{o}}),\] \[4sin(\theta +{{60}^{o}}))\]of the circle \[{{x}^{2}}+{{y}^{2}}=16\]is             

    A)  \[4\]                                    

    B)  \[8\]

    C)  \[16\]                                  

    D)  \[2\]

    Correct Answer: A

    Solution :

    Length of the chord \[=\sqrt{\begin{align}   & {{[4\cos (\theta +{{60}^{o}})-4\cos \theta ]}^{2}} \\  & +{{[4\sin (\theta +{{60}^{o}})-4\sin \theta ]}^{2}} \\ \end{align}}\] \[=4\sqrt{\begin{align}   & {{\cos }^{2}}(\theta +{{60}^{o}})+{{\cos }^{2}}\theta +{{\sin }^{2}}(\theta +{{60}^{o}}) \\  & +{{\sin }^{2}}\theta -2\cos (\theta +{{60}^{o}})\cos \theta  \\  & -2\sin (\theta +{{60}^{o}})\sin \theta  \\ \end{align}}\] \[=4\sqrt{1+1-2\cos \,{{60}^{o}}}=4\]


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