A) \[PC{{l}_{3}}\]
B) \[PC{{l}_{5}}\]
C) \[SOC{{l}_{2}}\] in presence of pyridine
D) dry \[HCl\] in the presence of anhydrous \[ZnC{{l}_{2}}\]
Correct Answer: C
Solution :
The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with \[SOC{{l}_{2}}\] in the presence of pyridine. \[ROH+SOC{{l}_{2}}\xrightarrow{{}}RCl+HCl+S{{O}_{2}}\] The other products being gases escape leaving behind pure alkyl halide.
You need to login to perform this action.
You will be redirected in
3 sec
