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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    30 cc of \[\frac{M}{3}HCl,\,20\,cc\] of \[\frac{M}{2}HN{{O}_{3}}\] and 40 cc of \[\frac{M}{4}NaOH\] solutions are mixed and the volume was made up to \[1\text{ }d{{m}^{3}}\]. The pH of the resulting solution is

    A)  8                                            

    B)  2

    C)  1                                            

    D)  3

    Correct Answer: B

    Solution :

    Total milli equivalents of \[{{H}^{+}}\]                 \[=30\times \frac{1}{3}+20\times \frac{1}{2}=20\] Total milli equivalents of \[O{{H}^{-}}\]                 \[=40\times \frac{1}{4}=10\] Milli equivalence of \[{{H}^{+}}\] left                 = 20 - 10 = 10 \[\therefore \]  \[[{{H}^{+}}]=\frac{10}{1000}g\,ions/d{{m}^{3}}={{10}^{-2}}\] \[\therefore \]                  \[pH=2\]


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