CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    A body of mass m moving along a straight line covers half the distance with a speed of \[2\text{ }m{{s}^{-1}}\]. The remaining half of the distance is covered in two equal time intervals with a speed of \[3\text{ }m{{s}^{-1}}\] and \[5\text{ }m{{s}^{-1}}\] respectively. The average speed of the particle for the entire journey is

    A)  \[\frac{3}{8}m{{s}^{-1}}\]                           

    B)  \[\frac{3}{8}m{{s}^{-1}}\]

    C)  \[\frac{4}{3}m{{s}^{-1}}\]                           

    D)  \[\frac{16}{3}m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    Let the total distance travelled by the body is 2S. If \[{{t}_{1}}\] is the time taken by the body to travel first half of the distance, then                 \[{{t}_{1}}=\frac{S}{2}\] Let \[{{t}_{2}}\] be the time taken by the body for each time interval for the remaining half journey. \[\therefore \]  \[S=3\,{{t}_{2}}+5{{t}_{2}}=8\,{{t}_{2}}\] So, average speed \[=\frac{Total\text{ }distance\text{ }travelled}{Total\text{ }time\text{ }taken}\]                                 \[=\frac{2S}{{{t}_{1}}+2{{t}_{2}}}\]                                 \[=\frac{2S}{\frac{S}{2}+\frac{S}{4}}\]                                 \[=\frac{8}{3}m{{s}^{-1}}\]


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