A) \[\frac{1}{3}\]
B) \[\sqrt{3}\]
C) \[\frac{1}{\sqrt{3}}\]
D) 3
Correct Answer: C
Solution :
de-Broglie wavelength of an electron is given by \[\lambda =\frac{h}{mv}=\frac{h}{\sqrt{2mK}}\] or \[\lambda \propto \frac{1}{\sqrt{K}}\] \[\therefore \] \[\frac{\lambda '}{\lambda }=\frac{1}{\sqrt{3K}}=\frac{\sqrt{K}}{1}=\frac{1}{\sqrt{3}}\] or \[\lambda '=\frac{\lambda }{\sqrt{3}}\] Hence, de-Broglie wavelength will change by factor \[\frac{1}{\sqrt{3}}\].
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