CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    The value of \[\tan \,67\frac{{{1}^{o}}}{2}+\cos 67\frac{{{1}^{o}}}{2}\] is

    A)  \[\sqrt{2}\]                                       

    B)  \[3\sqrt{2}\]

    C)  \[2\sqrt{2}\]                     

    D)  \[2-\sqrt{2}\]

    Correct Answer: C

    Solution :

    Now,  \[\tan 67\frac{1}{2}{}^\circ +\cot 67\frac{1}{2}{}^\circ \] \[=\tan \left( {{90}^{o}}-22\frac{1}{2}{}^\circ  \right)+\cot \left( {{90}^{o}}-22\frac{1}{2}{}^\circ  \right)\]\[=\tan 22\frac{1}{2}{}^\circ +\cot 22\frac{1}{2}{}^\circ \] \[=\sqrt{2}-1+\sqrt{2}+1\] \[=2\sqrt{2}\]


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