CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    The number of solutions for the equation \[\sin 2x+\cos 4x=2\] is

    A)  \[0\]                                    

    B)  \[1\]

    C)  \[2\]                                    

    D)  \[\infty \]

    Correct Answer: A

    Solution :

    Given, \[\sin \,2x+cos\,4x=2\] \[\Rightarrow \]               \[\sin \,2x+1-2si{{n}^{2}}2x=2\] \[\Rightarrow \]               \[2{{\sin }^{2}}2x-sin\,\,2x+1=0\] Now, Discriminant, \[D={{(-1)}^{2}}-4.2.1=-7<0\] Hence, it is an imaginary equation, so the real roots does not exist.


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