CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    The equation of the smallest circle passing through the points \[(2,2)\] and \[(3,3)\] is

    A)  \[{{x}^{2}}+{{y}^{2}}+5x+5y+12=0\]

    B)  \[{{x}^{2}}+{{y}^{2}}-5x-5y+12=0\]

    C)  \[{{x}^{2}}+{{y}^{2}}+5x-5y+12=0\]

    D)  \[{{x}^{2}}+{{y}^{2}}-5x+5y-12=0\]

    Correct Answer: B

    Solution :

    Let the points be \[A=(2,\,\,2)\] and \[B=(3,\,3)\] Since, the circle passing through these points, so they satisfie the equation of the circle. Now, taking option , Let   \[S\equiv {{x}^{2}}+{{y}^{2}}-5x-5y+12=0\] At     \[A=(2,2)\] \[{{2}^{2}}+{{2}^{2}}-5(2)-5(2)+12=0\] \[\Rightarrow \]               \[0=0\] At   \[B=(3,3)\]                 \[{{3}^{2}}+{{3}^{2}}-5(3)-5(3)+12=0\] \[\Rightarrow \]               \[0=0\] Hence, option [b] is correct.


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