A) \[Zn/HCl\]
B) \[Sn/HCl\]
C) \[Zn-Hg/HCl\]
D) \[Pd-{{H}_{2}}\]
Correct Answer: D
Solution :
Alkynes are converted into alkenes by using Lindlar?s catalyst \[({{H}_{2}}/Pd)\] \[\underset{Alkyne}{\mathop{R-C\equiv R-R}}\,\xrightarrow{{{H}_{2}}/Pd}R-\underset{cis\text{ }alkene}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,=\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-R\]
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