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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    Three moles of \[PC{{l}_{5}}\], three moles of \[PC{{l}_{3}}\]and two moles of \[C{{l}_{2}}\] are taken in a closed vessel. If at equilibrium the vessel has 1.5 moles of\[PC{{l}_{5}}\], the number of moles of \[PC{{l}_{3}}\] present in it is

    A)  5                                            

    B)  3

    C)  6                                            

    D)  4.5

    Correct Answer: D

    Solution :

    \[PC{{l}_{5}}\] \[\rightleftarrows \] \[PC{{l}_{3}}\] + \[C{{l}_{2}}\]
    3 mol 3 mol 2 mol initially
    \[(3-x)\,mol\] \[(3+x)\,mol\] \[(2+x)\,mol\]at equilibrium
    \[\because \]     \[3-x=1.5\]                 \[x=1.5\]              Number of moles of \[PC{{l}_{3}}=3+x\]                                 \[=3+1.5=4.5\]


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