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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    With what velocity should an observer approach a stationary sound source, so that the apparent frequency of sound should appear double the actual frequency? (v is velocity of sound).

    A)  \[\frac{v}{2}\]                                  

    B)  3 v

    C)  2 v                                        

    D)  v

    Correct Answer: D

    Solution :

    By using               \[v'=v\left[ \frac{v-{{v}_{o}}}{v-{{v}_{s}}} \right]\]                                 \[2v'=v\left[ \frac{v-{{v}_{o}}}{v-0} \right]\] \[\Rightarrow \]                               \[{{v}_{o}}=-v\]. Negative sign indicates that observer is moving opposite to the direction of velocity of sound.


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