A) \[{{F}_{n}}>>{{F}_{e}}\]
B) \[{{F}_{n}}={{F}_{e}}\]
C) \[{{F}_{n}}<<{{F}_{e}}\]
D) \[{{F}_{n}}\approx {{F}_{e}}\]
Correct Answer: C
Solution :
\[{{F}_{n}}\] is stronger than \[{{F}_{e}}.\,{{F}_{n}}\] operates at very short range inside the nucleus as little as \[{{10}^{-15}}m\]. As in the given case two protons are kept at a separation of \[40\,\overset{o}{\mathop{A}}\,\,{{F}_{n}}<<{{F}_{e}}\].
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