CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to 1 division. The galvanometer resistance is

    A)  \[100\,\Omega \]                           

    B)  \[99\,\Omega \]

    C)  \[10\,\Omega \]                             

    D)  \[9.9\,\Omega \]

    Correct Answer: B

    Solution :

    Shunt is connected to the galvanometer                 \[{{i}_{g}}=\frac{i\,S}{S+G}\]                 \[1=\frac{100\times 1}{(1+G)}\] \[\Rightarrow \]               \[G=99\,\Omega \]


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