CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    \[{{7}^{2{{\log }_{7}}5}}\]is equal to

    A)  \[{{\log }_{7}}35\]                          

    B)  \[5\]

    C)  \[25\]                                  

    D)  \[{{\log }_{7}}25\]

    Correct Answer: C

    Solution :

    Given,   \[{{7}^{2{{\log }_{7}}5}}\] \[={{7}^{{{\log }_{7}}{{(5)}^{2}}}}\]          [ \[\because \] \[{{a}^{{{\log }_{a}}x}}=x,x>0,x\ne 0,1\]] \[={{(5)}^{2}}=25\]


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