CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    If \[\vec{a}=2\hat{i}+3\hat{j}-k,\] \[\vec{b}=\hat{i}+2\hat{j}-5\hat{k},\] \[\vec{c}=3\hat{i}+5\hat{j}-\hat{k},\]Then a vector perpendicular to \[\vec{a}\]and in the plane containing \[\overrightarrow{b}\] and \[\overrightarrow{c}\] is

    A)  \[-17\hat{i}+21\hat{j}-97\hat{k}\]

    B)  \[17\hat{i}+21\hat{j}-123\hat{k}\]

    C)  \[-17\hat{i}-21\hat{j}+97\hat{k}\]

    D) \[-17\hat{i}-21\hat{j}-97\hat{k}\]

    Correct Answer: D

    Solution :

    We know that a vector perpendicular to \[\vec{a}\] and in the plane containing \[\vec{b}\] and \[\vec{c}\] is given by \[\vec{a}\times (\vec{b}\times \vec{c})\] Given \[\vec{a}=2\hat{i}+3\hat{j}-\hat{k},\] \[\vec{b}=\hat{i}+2\hat{j}-5\hat{k}\] and \[\vec{c}=3\hat{i}+5\hat{j}-\hat{k}\] \[\therefore \]\[\vec{b}\times \vec{c}=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    1 & 2 & -5  \\    3 & 5 & -1  \\ \end{matrix} \right|=23\hat{i}-14\hat{j}-\hat{k}\] Now, \[\vec{a}\times (\vec{b}\times \vec{c})=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    2 & 3 & -1  \\    23 & -14 & -1  \\ \end{matrix} \right|\] \[=(-3-14)\hat{i}-\hat{j}(-2+23)+\hat{k}(-28-69)\] \[=-17\hat{i}-21\hat{j}-97\hat{k}\] Which is the required vector.


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