A) 0.50 L of \[10\text{ }N\,HCl\] and 0.50 L of 4 N \[HCl\]
B) 0.60 L of \[10\text{ }N\,HCl\] and 0.40 L of 4 N \[HCl\]
C) 0.80 L of \[10\text{ }N\,HCl\] and 0.20 L of 4 N \[HCl\]
D) 0.75 L of \[10\text{ }N\,HCl\] and 0.25 L of 4 N \[HCl\]
Correct Answer: A
Solution :
Let V litre of \[10\text{ }N\,HCl\] be mixed with (1 - V) litre of \[4\text{ }N\,HCl\] to give \[(V+1V)=1\text{ }L\] of\[7\,N\,HCl\]. \[{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}=N\,V\] \[10\,V+4\,(1-V)=7\times 1\] \[10\,V+4-4\,V=7\] \[6\,V=7-4\] \[V=\frac{3}{6}=0.50\,L\] Volume of \[10\,N\,HCl=0.50\,L\] Volume of \[4\,N\,HCl=1-0.50=0.50\,L\]
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