A) 2 g of carbon monoxide
B) 2 g of carbon dioxide
C) 2 g of sulphur dioxide
D) 2 g of water
Correct Answer: D
Solution :
Number of oxygen atom in 2 g of \[CO\] \[=\frac{2}{28}\times 6.022\times {{10}^{23}}\times 1\] Number of oxygen atom in 2 g of \[C{{O}_{2}}\] \[=\frac{2}{44}\times 6.022\times {{10}^{23}}\times 2\] Number of oxygen atom in 2 g of \[S{{O}_{2}}\] \[=\frac{2}{64}\times 6.022\times {{10}^{23}}\times 2\] Number of oxygen atom in 2 g of \[{{H}_{2}}O\] \[=\frac{2}{18}\times 6.022\times {{10}^{23}}\times 1\] Hence, 2 g of \[{{H}_{2}}O\] has maximum number of atoms of oxygen.
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