A) \[{{[Au{{(CN)}_{2}}]}^{-}}\] and \[{{[Zn{{(CN)}_{6}}]}^{4-}}\]
B) \[{{[Au{{(CN)}_{4}}]}^{2-}}\] and \[{{[Zn{{(CN)}_{4}}]}^{2-}}\]
C) \[{{[Au{{(CN)}_{4}}]}^{3-}}\] and \[{{[Zn{{(CN)}_{4}}]}^{2-}}\]
D) \[{{[Au{{(CN)}_{2}}]}^{-}}\] and \[{{[Zn{{(CN)}_{4}}]}^{2-}}\]
Correct Answer: D
Solution :
\[4Au+8C{{N}^{-}}+2{{H}_{2}}O+{{O}_{2}}\xrightarrow{{}}\underset{soluble}{\mathop{4{{[Au{{(CN)}_{2}}]}^{-}}}}\,\] \[+4O{{H}^{-}}\] \[2{{[Au{{(CN)}_{2}}]}^{-}}+Zn\xrightarrow{{}}2Au(s)\downarrow +{{[Zn{{(CN)}_{4}}]}^{2-}}\]
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