CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    The surface temperature of the sun which has maximum energy emission at 500 nm is 6000 K. The temperature of a star which has maximum energy emission at 400 nm will be

    A)  8500 K                 

    B)  4500 K

    C)  7500 K                 

    D)  6500 K

    Correct Answer: C

    Solution :

    By using Wien*s displacement law,                 \[{{({{\lambda }_{m}})}_{1}}\,{{T}_{1}}={{({{\lambda }_{m}})}_{2}}{{T}_{2}}\] \[\Rightarrow \]               \[500\times 6000=400\times {{T}_{2}}\] \[\Rightarrow \]                               \[{{T}_{2}}=\frac{500\times 6000}{400}\]                 \[{{T}_{2}}=7500\,K\]


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