question_answer

An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be :

A)  \[{{A}_{3}}{{B}_{6}}\]                   

B)  \[{{A}_{2}}{{B}_{3}}\]

C)  \[{{A}_{3}}{{B}_{2}}\]                   

D)  \[{{A}_{2}}B\]

Correct Answer: B

Solution :

A has three electrons in its outermost orbit, it valency is 3. B has six electrons in its outermost orbit, it valency = 2 formula of the compound \[={{A}_{2}}{{B}_{3}}\]