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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    In the circuit given \[E=6.0\]volt, \[{{R}_{1}}=100\,\Omega \]\[{{R}_{2}}={{R}_{3}}=50\,\,\Omega ,{{R}_{4}}=75\,\,\Omega \]. The equivalent resistance of the circuit, in ohms, is:

    A)  11.875                                 

    B)  26.31

    C)  118.75                                 

    D)  none of these

    Correct Answer: C

    Solution :

    \[{{R}_{2}}\,,\,\,{{R}_{3}}\] and \[{{R}_{4}}\] are m parallel order, so their equivalent resistance                 \[\frac{1}{R}=\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}+\frac{1}{{{R}_{4}}}\]                 \[=\frac{1}{50}+\frac{1}{50}+\frac{1}{75}=\frac{30+30+20}{1500}\]                 \[=\frac{80}{1500}=\frac{4}{75}\] \[\therefore \]  \[R=\frac{75}{4}\,\,\Omega \]                 \[R={{R}_{1}}+R\]                 \[=100+\frac{75}{4}\]                 \[=\frac{475}{4}\Omega \]                 \[118.75\,\Omega \]


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