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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The current in a simple series circuit is 5.0 amp. When an additional resistance of 2.0 ohms is inserted, the current drops to 4.0 amp. The original resistance of the circuit in ohms was:

    A)  1.25                                      

    B)  8

    C)  10                                         

    D)  20

    Correct Answer: B

    Solution :

    Let the original resistance is \[R\,\Omega \]. \[\therefore \]  \[V=I\,R\]                 \[V=5\times R=5\,R\]                                     ... (i) When \[2\,\Omega \]. resistance is inserted, then total resistance \[=(R+2)\,\Omega \] \[\therefore \]  \[V=I\,(R+2)=4\,(R+2)\]                                ... (ii) From Eqs. (i) and (ii), we get                 \[5R=4(R+2)\] \[\therefore \]  \[R=8\,\,\Omega \]


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