A) \[N{{m}^{-1}}\]
B) \[N{{m}^{-2}}\]
C) dyne \[c{{m}^{-2}}\]
D) mega pascal
Correct Answer: A
Solution :
\[y=\frac{stress}{strain}=N/{{m}^{2}}\] or pascal (in SI system) and \[y=\frac{dyne}{c{{m}^{2}}}\] (in C.G.S. system) Thus, \[N{{m}^{-1}}\] is not the unit of Youngs modulus.
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