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  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    The radius of the circle passing through the point (6, 2) and two of whose diameters are \[x+y=6\] and \[x+2y=4\] is :

    A)  4                                            

    B)  6

    C)  20                                         

    D)  \[\sqrt{20}\]

    Correct Answer: D

    Solution :

    Centre is point of intersection of two diameters i.e., the point is C (8, - 2) \[\therefore \]  \[r=CP=\sqrt{4+16}=\sqrt{20}\]                 \[=2\sqrt{5}\]


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