A) \[p\to q\]
B) \[q\to p\]
C) \[\sim (p\to q)\]
D) \[\sim (q\to p)\]
Correct Answer: D
Solution :
By using truth table, we know that the proposition \[\sim \,(p\wedge q)\overset{{}}{\longleftrightarrow}\sim \,(p\vee \sim q)\] or \[\sim \,p\wedge q\] is logically equivalent to \[\sim \,(p\to q)\].
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