A) 445 kJ
B) 278 kJ
C) -890 kJ
D) 178 kJ
Correct Answer: D
Solution :
The combustion of methane can be represented by the following equation : \[\underset{12+4=16}{\mathop{C{{H}_{4}}+2{{O}_{2}}}}\,\xrightarrow{{}}C{{O}_{2}}+2{{H}_{2}}O+890\,\,kJ\] \[\therefore \] 16g \[C{{H}_{4}}\] burns in air to liberate = 890 kJ of heat \[\therefore \] 3.2g \[C{{H}_{4}}\] will liberate \[=\frac{890\times 3.2}{16}\] = 178 kJ of heat
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