A) \[Hg{{(OH)}_{2}}\]
B) \[HgC{{O}_{3}}\,.\,HgO\]
C) \[HgC{{O}_{3}}\]
D) \[HgC{{O}_{3}}\,.\,Hg{{(OH)}_{2}}\]
Correct Answer: B
Solution :
Basic mercuric carbonate is obtained in this reaction. \[N{{a}_{2}}C{{O}_{3}}+2HgC{{l}_{2}}\xrightarrow{{}}HgC{{O}_{3}}\,.\,\,HgO\] \[+2NaCl+C{{l}_{2}}+C{{O}_{2}}\]
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