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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    The reaction, \[2\,S{{O}_{2(g)}}+{{O}_{2(g)}}2S{{O}_{3(g)}}\] is carried out in a \[1\,\,d{{m}^{3}}\] vessel and \[2\,\,d{{m}^{3}}\] vessel separately. The ratio of the reaction velocities will be:

    A)  1 : 8                                      

    B)  1 : 4

    C)  4 : 1                                      

    D)  8 : 1

    Correct Answer: D

    Solution :

    \[2S{{O}_{2}}(g)+{{O}_{2}}(g)2S{{O}_{3}}(g)\] For this reaction, rate                 \[({{r}_{1}})=k\,[S{{O}_{2}}]_{1}^{2}{{[{{O}_{2}}]}_{1}}\]                               ... (1) On doubling the volume of vessel, concentration would be half. Hence, rate        \[({{r}_{2}})=k{{\left( \frac{{{[S{{O}_{2}}]}_{1}}}{2} \right)}^{2}}\left( \frac{{{[{{O}_{2}}]}_{1}}}{2} \right)=\frac{{{r}_{1}}}{8}\]                 \[\frac{{{r}_{1}}}{{{r}_{2}}}=8:1\]


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