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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    An artificial radioactive isotope gave 7 N after two successive P-particle emissions. The number of neutrons in the parent nucleus must be:

    A)  9                                            

    B)  14

    C)  5                                            

    D)  7

    Correct Answer: A

    Solution :

    Atomic number increases by one after the emission of one \[\beta \]-particle. Hence, the parent nucleus (which on two successive \[\beta \] -emission gave \[_{7}{{N}^{14}}\]) must be \[_{5}{{X}^{14}}\] Hence, number of neutrons in parent nucleus = 14 - 5 = 9


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