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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    Same amount of electric current is passed through solutions of \[AgN{{O}_{3}}\] and \[HCl\]. If 1.08 g of silver is obtained in the first case, the amount of hydrogen liberated at S.T.P. in the second case is :

    A)  \[224\,c{{m}^{3}}\]                       

    B)  1.008 g

    C)  \[112\,c{{m}^{3}}\]                       

    D)  \[22400\,c{{m}^{3}}\]

    Correct Answer: C

    Solution :

    According to Faradays second law of electrolysis, we have                 \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] \[\therefore \]  \[\frac{1.08}{x}=\frac{108}{1}\] \[\therefore \] weight of hydrogen \[(x)=0.01\,g\] Hence, the volume of hydrogen at                 \[STP=\frac{22400\times 0.01}{2}=112\,\,c{{m}^{3}}\]


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