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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    The time taken by A.C. of 50 Hz in reaching from zero to the maximum value is:

    A)  \[50\times {{10}^{-3}}sec\]        

    B)  \[5\times {{10}^{-3}}sec\]

    C)  \[1\times {{10}^{-3}}sec\]          

    D)  \[2\times {{10}^{-3}}sec\]

    Correct Answer: B

    Solution :

    The time taken by a.c in reaching from zero to maximum value is                 \[t=\frac{T}{4}=\frac{T}{4f}=\frac{1}{50\times 4}=5\times {{10}^{-3}}\sec \]


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