CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    A sound source is moving towards stationary listener with \[\frac{1}{10}\]th of the speed of sound. The ratio of apparent to real frequency is:

    A)  \[{{\left( \frac{9}{10} \right)}^{2}}\]                       

    B)  \[\frac{10}{9}\]

    C)  \[\frac{11}{10}\]                                             

    D)  \[{{\left( \frac{11}{10} \right)}^{2}}\]

    Correct Answer: B

    Solution :

    Given: \[{{n}_{s}}=\frac{n}{10}\] Apparent frequency \[n=n\left( \frac{\upsilon }{\upsilon -{{\upsilon }_{s}}} \right)\] where n = real frequency ot source \[\upsilon =\] velocity of sound \[{{\upsilon }_{s}}=\] velocity of source So           \[\frac{n}{n}=\frac{\upsilon }{\upsilon -\frac{\upsilon }{10}}\]                 \[=\frac{10}{9}\]


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