A) decreased by 25%
B) increased by 25%
C) decreased by 66.7%
D) increased by 77.7%
Correct Answer: D
Solution :
Given : \[{{r}_{1}}=4\] metre, so by inverse square rule \[E\propto \frac{1}{{{r}^{2}}}\] \[{{r}_{2}}=3\] metre \[\left( \frac{{{E}_{2}}}{{{E}_{1}}}-1 \right)\times 100=\left( \frac{16}{9}-1 \right)\times 100\] \[=\frac{700}{9}=77.7%\]
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