A) increase the resolving power of the telescope
B) increase the magnifying power of the telescope
C) to focus on distant objects
D) make image aberrationless
Correct Answer: A
Solution :
Resolving power of the telescope is \[=\frac{a}{1.22\,\lambda }\] where a = diameter of aperture of objective lens \[\lambda =\] wavelength of light Therefore, resolving power \[\propto \,a\] As aperture of the objective lens increases, resolving power of telescope increases.
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