CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    The amplitude of \[\sin \frac{\pi }{5}+i\left( 1-\cos \frac{\pi }{5} \right)\] is :

    A)  \[\frac{2\pi }{5}\]                                           

    B)  \[\frac{\pi }{5}\]

    C)  \[\frac{\pi }{15}\]                                           

    D)  \[\frac{\pi }{10}\]

    Correct Answer: D

    Solution :

    Let \[z=\sin \frac{\pi }{5}+i\left( 1-\cos \frac{\pi }{5} \right)\] Then, amp \[={{\tan }^{-1}}\left( \frac{1-\cos \frac{\pi }{5}}{\sin \frac{\pi }{5}} \right)\]                      \[={{\tan }^{-1}}\left( \frac{2{{\sin }^{2}}\pi /10}{2\sin \frac{\pi }{10}\cos \frac{\pi }{10}} \right)\]                                 \[\left[ \begin{align}   & 1-\cos 2\theta =2{{\sin }^{2}}\theta  \\  & \sin 2\theta =2\sin \theta \cos \theta  \\ \end{align} \right]\]                 \[={{\tan }^{-1}}\left( \tan \frac{\pi }{10} \right)\]                 \[=\frac{\pi }{10}\]


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