CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    If \[x=a\,(\theta -\sin \theta ),\,y=a\,(1-\cos \theta )\] then \[\frac{dy}{dx}\] is equal to :

    A)  \[\cot \theta /2\]                           

    B)  \[\tan \theta /2\]

    C)  \[\frac{1}{2}\cos e{{c}^{2}}\frac{\theta }{2}\]                    

    D)  \[-\frac{1}{2}\cos e{{c}^{2}}\frac{\theta }{2}\]

    Correct Answer: A

    Solution :

    Here                 \[x=a\,(\theta -\sin \theta )\] and \[y=a\,(1-\cos \theta )\]                 \[\frac{dx}{d\theta }=a\,(1-\cos \theta )\]                 \[\frac{dy}{d\theta }=a\sin \theta \] \[\therefore \]  \[\frac{dy}{dx}=\frac{dy}{d\theta }\times \frac{d\theta }{dx}=\frac{a\sin \theta }{a\,(1-\cos \theta )}\]                 \[=\frac{\sin \theta }{1-\cos \theta }\]                 \[=\frac{2\sin \frac{\theta }{2}\cos \frac{\theta }{2}}{2{{\sin }^{2}}\frac{\theta }{2}}\]                 [\[\sin 2\theta =2\sin \theta \cos \theta \]and \[1-{{\cos }^{2}}\theta =2{{\sin }^{2}}\theta \]]                                 \[=\cot \frac{\theta }{2}\]


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