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  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    Kinetic energy of one mole of an ideal gas at 300 K in kJ is :

    A)  3.74                                      

    B)  348

    C)  34.8                                      

    D)  3.48

    Correct Answer: A

    Solution :

    Kinetic energy \[(K.E.)=\frac{3}{2}RT\] \[\therefore \]  \[K.E.=\frac{3}{2}\times 8.31\times 300\] Joule                 = 3.74 kJ


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