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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    The equivalent weight of a certain trivalent element is 20. Molecular, weight of its oxide is:

    A)  152                                       

    B)  56

    C)  168                                       

    D)  68

    Correct Answer: C

    Solution :

    Atomic weight of element, M = equivalent weight x valency                 \[=20\times 3\]                 = 60 Molecular formula of its oxide \[={{M}_{2}}{{O}_{3}}\] Hence, molecular weight of oxide                 \[=2\times 60+3\times 12\]                 = 120 + 48


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