CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    Temperature coefficient of a reaction is 2. When temperature is increased from \[{{30}^{o}}C\] to\[{{100}^{o}}C\], rate of the reaction increases by :

    A)  128 times           

    B)  100 times

    C)  500 times           

    D)  250 times

    Correct Answer: A

    Solution :

    Temperature coefficient\[=\frac{rate\text{ }of\text{ }reaction\text{ }at\text{ }{{35}^{o}}C}{rate\text{ }of\text{ }reaction\text{ }at\text{ }{{25}^{o}}C}=2\] Thus, increase in rate is 2 times, when temperature is increased \[{{10}^{o}}C\]. Hence, by the increase of \[{{70}^{o}}C\,(100-30={{70}^{o}}C)\], the increase in rate will be                                 \[={{(2)}^{7}}\]                 \[(\because \,\,{{70}^{o}}=7\times {{10}^{o}})\]                 = 128 times


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