A) \[\frac{2{{E}^{2}}{{t}^{2}}}{mq}\]
B) \[\frac{E{{q}^{2}}m}{2{{t}^{2}}}\]
C) \[\frac{Eqm}{t}\]
D) \[\frac{{{E}^{2}}{{q}^{2}}{{t}^{2}}}{2m}\]
Correct Answer: D
Solution :
Electrostatic force on charged particle \[F=qE\] So, by Newtons law of motion \[F=ma=qE\] or \[a=\frac{qE}{m}\] Velocity attained by particle \[v=0+\frac{qE}{m}t\] So, kinetic energy \[K=\frac{1}{2}m{{v}^{2}}\] \[K=\frac{1}{2}\frac{m{{q}^{2}}{{E}^{2}}}{{{m}^{2}}}{{t}^{2}}=\frac{{{E}^{2}}{{q}^{2}}{{t}^{2}}}{2m}\]
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