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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2002

  • question_answer
    \[_{z}{{X}^{M}}+{{\,}_{2}}H{{e}^{4}}\to {{\,}_{15}}{{P}^{30}}+{{\,}_{0}}{{n}^{1}}.\]Then:

    A) \[Z=12,M=27\] 

    B) \[Z=13,M=27\]

    C)  \[Z=12,M=17\]

    D) \[Z=13,M=28\]

    Correct Answer: B

    Solution :

    \[{{\,}_{Z}}{{X}^{M}}+{{\,}_{2}}H{{e}^{4}}\xrightarrow{{}}{{\,}_{15}}{{P}^{30}}+{{\,}_{0}}{{n}^{1}}\] Here \[Z=13\]and \[M=17\] Hence \[{{\,}_{13}}{{X}^{17}}+{{\,}_{2}}H{{e}^{4}}\xrightarrow{{}}{{\,}_{15}}{{P}^{30}}+\,{{ & }_{0}}{{n}^{1}}\]


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