A) \[45\text{ }g\]of \[MgO\]and\[~15\text{ }g\] of\[{{O}_{2}}\]
B) \[50\text{ }g\]of\[~MgO\] and \[10\text{ }g\]of\[~{{O}_{2}}\]
C) \[60\text{ }g\] of\[MgO\]only
D) \[~40\text{ }g\] of \[MgO\]and \[20\text{ }g\]of \[{{O}_{2}}.\]
Correct Answer: B
Solution :
Mg and oxygen reacts as \[\underset{(48)}{\mathop{\underset{2\,\times \,24}{\mathop{2Mg}}\,}}\,+\underset{(32)}{\mathop{\underset{32}{\mathop{{{O}_{2}}}}\,}}\,\xrightarrow{{}}\underset{(80)}{\mathop{\underset{2\,\times \,40}{\mathop{2MgO}}\,}}\,\] 48 gm of Mg produce 80 gm of MgO \[\therefore \]30 gm of Mg produce \[\frac{80\times 30}{48}=50\,gm\] \[\because \]48 gm of Mg reacts with 32 gm of oxygen \[\therefore \]30 gm of Mg reacts with \[\frac{32\times 30}{48}=10\,gm.\]
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