A) will be in equilibrium if the charges rotate about the centre of the triangle
B) can never be in equilibrium
C) will be in equilibrium if the charges have the same magnitudes but different signs
D) will be in equilibrium if the charges have different magnitude and different signs.
Correct Answer: B
Solution :
No. of atoms in 10 gm of copper \[=\frac{6\times {{10}^{23}}\times 10}{63.5}=9.4\times {{10}^{22}}\] No. of \[\bar{e}\]transferred from one piece to other \[=\frac{9.4\times {{10}^{22}}}{{{10}^{6}}}=9.4\times {{10}^{16}}\] Charge on these electron \[\bar{e}=9.4\times {{10}^{16}}\times 1.6\times {{10}^{-19}}\] \[=15\times {{10}^{-3}}C\] equal but opposite charge will be on other piece \[\therefore \] \[{{F}_{\text{attraction}}}=\frac{{{q}_{1}}{{q}_{2}}}{4\pi \,{{\varepsilon }_{0}}\,{{r}^{2}}}\] \[=\frac{{{(1.5\times {{10}^{-2}})}^{2}}\times 9\times {{10}^{9}}}{0.01}\] \[=2\times {{10}^{7}}\,N\]
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